92=5w^2+3w

Solution for 92=5w^2+3w equation:

92=5w^2+3w

We move all terms to the left:

92-(5w^2+3w)=0

We get rid of parentheses

-5w^2-3w+92=0

a = -5; b = -3; c = +92;
Δ = b2-4ac
Δ = -32-4·(-5)·92
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-43}{2*-5}=\frac{-40}{-10}
=+4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+43}{2*-5}=\frac{46}{-10}
=-4+3/5
$